Website online-offline checker using PHP
In this tutorial you will learn how to create a website online-offline checker using PHP and cURL.
This can be easily achieved with just few lines of code. What we need to do is to make a request to the website in question and see, if it’s server is responding. If it is – it’s most likely online.
As I mentioned above, it is easy as 25 lines of code. You can use this method with AJAX call as well.
* Disclaimer: The below check can be achieved with a lot of different methods. For this tutorial I choose cURL, as it’s more interesting
Let’s get started and create our website online-offline checker using PHP (ofcourse). The main purpose is to check, if the web server is responding to our request.
[code language=”php”]
<?php
// Our main function
function checkIfOnline($url) {
// Setting the url
$curlInit = curl_init($url);
// Set the timeout
curl_setopt($curlInit, CURLOPT_CONNECTTIMEOUT, 10);
// passing the headers to the data stream
curl_setopt($curlInit, CURLOPT_HEADER, true);
// Doing a request without getting the body
curl_setopt($curlInit, CURLOPT_NOBODY, true);
// TRUE to return the transfer as a string of the return value of curl_exec() instead of outputting it out directly
curl_setopt($curlInit, CURLOPT_RETURNTRANSFER, true);
// Get response
$status= curl_exec($curlInit);
curl_close($curlInit);
if ($status) {
return true;
} else {
return false;
}
}
// Call the function and get the result – you can pass the URL as a parameter in a GET request
if (checkIfOnline(‘gelasoft.com’)) {
echo "Up";
} else {
echo "Down"; // Or return an error code
}
[/code]
If you follow this tutorial step by step, you have your own working website online-offline checker using PHP and cURL.
If you have any questions and suggestions, feel free to leave a comment below.
